(y+3)(y^2+y-1)=

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Solution for (y+3)(y^2+y-1)= equation:


Simplifying
(y + 3)(y2 + y + -1) = 0

Reorder the terms:
(3 + y)(y2 + y + -1) = 0

Reorder the terms:
(3 + y)(-1 + y + y2) = 0

Multiply (3 + y) * (-1 + y + y2)
(3(-1 + y + y2) + y(-1 + y + y2)) = 0
((-1 * 3 + y * 3 + y2 * 3) + y(-1 + y + y2)) = 0
((-3 + 3y + 3y2) + y(-1 + y + y2)) = 0
(-3 + 3y + 3y2 + (-1 * y + y * y + y2 * y)) = 0
(-3 + 3y + 3y2 + (-1y + y2 + y3)) = 0

Reorder the terms:
(-3 + 3y + -1y + 3y2 + y2 + y3) = 0

Combine like terms: 3y + -1y = 2y
(-3 + 2y + 3y2 + y2 + y3) = 0

Combine like terms: 3y2 + y2 = 4y2
(-3 + 2y + 4y2 + y3) = 0

Solving
-3 + 2y + 4y2 + y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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